El astro de los Rolling Stones está de celebración ya que su hija mayor Jade se casa este sábado. Para la ceremonia se ha confirmado que Jagger cantará un clásicos de su banda.
La boda se llevará a cabo en los Cotswolds, Londres. Según el diario The Sun, el rockero cantará su clásico tema “You Can't Always Get What You Want” en la boda de la diseñadora de joyas de 41 años con el promotor y DJ Adrián Fillary.
En una breve declaración a la prensa inglesa, una fuente de la familia Jagger dijo: "Por supuesto que esto será entretenido para Mick".
La ceremonia se llevará a cabo en el mismo lugar donde la supermodelo Kate Moss y el líder de The Kills Jamie Hince se casaron el año pasado.
Jade Jagger se comprometió con Fillary en enero durante un viaje a Goa en la India.
Mick Jagger sing today at the wedding of his daughter Jade
The Rolling Stones star is celebrating because her oldest daughter Jade is getting married this Saturday. For the ceremony has been confirmed to sing a classic Jagger of his band.
The wedding will take place in the Cotswolds, London. According to The Sun, the rocker sings his classic song "You Can not Always Get What You Want" in wedding jewelry designer of 41 years with the promoter and DJ Adrian Fillary.
In a brief statement to the British press, a family source Jagger said: "Of course this will be fun for Mick."
The ceremony will take place in the same place where supermodel Kate Moss and Kills frontman Jamie Hince were married last year.
Jade Jagger is committed to Fillary in January during a trip to Goa in India.
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